Col. Greg Hanbuch

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Welcome to officers of both sides. Sit down and enjoy a drink served by our lovely barmaids Helga and Ingrid. Trade war stories or tall tales, but remember your deportment; that large man behind the counter will not hesitate to escort you out, if your behavior does not honor your rank!

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B. Kolcun
AotT
Posts: 159
Joined: Mon Jan 24, 2011 1:56 pm

Col. Greg Hanbuch

Post by B. Kolcun »

Officers of the AOC, <salute>

Please join me in congratulating Greg Hanbuch's promotion to Colonel. Well done, Colonel! Keep taking the fight to the Rebs.

<salute>

MG Brett Kolcun
AOC, Commanding
General Brett Kolcun
5/Cav/XIV
Army of the Cumberland
Douglas E Shaw
AotC
Posts: 152
Joined: Sun Sep 26, 2010 6:50 pm
Location: Webster Groves, MO

Re: Col. Greg Hanbuch

Post by Douglas E Shaw »

Congratulations Greg! I have been very impressed with your victories. You are doing a great job carrying on the AotC winning ways. Keep it up.
Gen Doug Shaw
4th Brig/1st Div/XIVth Corps
Robert Frost
AotC
Posts: 117
Joined: Sat Nov 13, 2010 11:16 am

Re: Col. Greg Hanbuch

Post by Robert Frost »

Great job, sir! Keep moving forward!
MG Robert Frost
I/XIV
Army of the Cumberland
Tom Lifsey
Posts: 41
Joined: Sat Mar 01, 2014 1:59 pm

Re: Col. Greg Hanbuch

Post by Tom Lifsey »

Congratulations. Well Deserved.
Lt. Col. Tom Lifsey
3rd Brigade, 1st Division, XIVth Corps, AotC
Antony Barlow
AotC
Posts: 313
Joined: Sun Aug 15, 2010 5:01 am
Location: Kingston Upon Hull, UK

Re: Col. Greg Hanbuch

Post by Antony Barlow »

Congratulations Greg! 8-)
John Fogarty
AotC
Posts: 186
Joined: Fri Aug 13, 2010 5:22 pm

Re: Col. Greg Hanbuch

Post by John Fogarty »

Congratulations Colonel!

A promising career in the AOC is in order!

regards,

MG John Fogarty
1st Division, XX Corps
David Danner
AotC
Posts: 851
Joined: Sun Aug 15, 2010 9:45 am
Location: Newark, Delaware

Re: Col. Greg Hanbuch

Post by David Danner »

Congratulations Greg---go 2nd Division................
Image
General Dave Danner
Commanding Cumberland Rifles Division, XX Corps
Army of the Cumberland
S = √ 30 x d x f + - e
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